Question

The sides of a triangle are 50cm.78cm&112cm the smallest altitude is

Answer 1

Answer:

Let

a = 50cm

b = 78cm

c = 112

S = a+b+c/2

S = 50+78+112/2

S = 240/2 = 120

Area = \sqrt{s(s-a)(s-b)(s-c)}

= \sqrt{120(120-50)(120-78)(120-112)}

= \sqrt{2822400}

= 1680 cm^{2}

Longest side = 120cm

corresponding to this side as the base the altitude will be smallest.

area =1/2 x base x altitude

=1680 = 1/2 x 112 x altitude

=altitude = 1680 x 2/112  

= 30cm 

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