Question

The sides of a triangle are 50cm 78cm and 112cm find the altitude to the largest side

Answer 1

given,

a=50cm

b=78cm

c=112cm

s=a+b+c/2

=50+78+112/2

=120cm

area=√s(s-a)(s-b)(s-c)

=√120(120-50)(120-78)(120-112)

=√120*70*42*8

=√2822400

=1680cm²

longest side =112cm

base =112cm

area =1/2 * base*height

1680=1/2*112*h

1680*2/112=h

h=30cm

hence, height is 30cm