The sides of a triangle are 56 cm,60 cm,52 cm long. the area of the triangle is
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let the given sides of triangle are
a = 56 cm ,b = 60 cm ,c = 52 cm
perimeter = 56 + 60 + 52= 168
semiperimeter (s )= 168 /2 = 84
area of triangle=√s (s - a ) (s - b ) (s - c )
=√{84 (84 - 56 ) (84 - 60) ( 84 - 52 )
=√( 84 × 28 × 24 × 32 )
=√1806336
=1344 cm^2
therefore , area of triangle = 1344 cm^2
______________________________
Your Answer : Area = 1344 cm^2
______________________________
a = 56 cm ,b = 60 cm ,c = 52 cm
perimeter = 56 + 60 + 52= 168
semiperimeter (s )= 168 /2 = 84
area of triangle=√s (s - a ) (s - b ) (s - c )
=√{84 (84 - 56 ) (84 - 60) ( 84 - 52 )
=√( 84 × 28 × 24 × 32 )
=√1806336
=1344 cm^2
therefore , area of triangle = 1344 cm^2
______________________________
Your Answer : Area = 1344 cm^2
______________________________
Answered by
0
THE ABOVE ANSWER IS HAVING COREECTION AS IT I HARD EVEN T READ ANSERS
let the given sides of triangle are
a = 56 cm ,b = 60 cm ,c = 52 cm
perimeter = 56 + 60 + 52= 168
semiperimeter (s )= 168 /2 = 84
area of triangle=√s (s - a ) (s - b ) (s - c )
=√{84 (84 - 56 ) (84 - 60) ( 84 - 52 )
=√( 84 × 28 × 24 × 32 )
=√1806336
=1344 cm^2
therefore , area of triangle = 1344 cm^2
______________________________
Your Answer : Area = 1344 cm^2
______________________________
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