Question

the sides of a triangle are 56cm,60cm,and 52cm long . find the area of the triangle

Answer 1

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$  

Assume

a = 52cm

b = 56cm

c = 60cm

Perimeter of ∆ = (a + b + c)

= 52 + 56 + 60

= 168 cm

$\tt{\rightarrow s = \dfrac{1}{2}\times (a + b + c)}$

$\tt{\rightarrow\dfrac{1}{2}\times 168}$

= 84 cm

(s - a) = (84 - 52) = 32cm

(s - b) = (85 - 56) = 28cm

(s - c) = (84 - 60) = 24cm

Herons Formula :-

$\tt{\rightarrow\sqrt{s(s-a)(s-b)(s-c)}}$

 $\tt{\rightarrow\sqrt{84\times 32\times 28\times 24}}$

 $\tt{\rightarrow\sqrt{14\times 6\times 16\times 2\times 14\times 2\times 6\times 4}}$

$\tt{\rightarrow\sqrt{14\times 6\times 4\times 2\times 2}}$

= 1344 cm²

★Area of triangle = 1344 cm²

Answer 2

Answer:

none of these

Step-by-step explanation: