Question

the sides of a triangle are 56cm,60cm and 62cm long then the area of the triangle is​

Answer 1

Step-by-step explanation:

$\star\sf\underline \purple{QuestioN}::-$

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is.

$\star\sf\underline\blue{Given} ::-$

Sides

A = 56cm

B = 60

C = 62

$\star\sf\underline \orange{To \: find}::-$

Area of triangle.?

$\star\sf\underline \pink{Formula}::-$

$\sf {Side = \frac{a + b + c}{c} }$

$\star\sf\underline \red{AnsweR}::-$

Using Heron's formula

Area of the triangle

$\sqrt{s(s - a) \: (s - b)(s - c)} \\ s = \frac{56 + 60 + 52}{2} \\ = > \red{84}$

$\sf{Area \: of \: triangle = } \red{\sqrt{84(84 - 60) \: (84- 56)(84 - 52)} } \\ \longrightarrow \sqrt{1806336} \\ \longrightarrow \bf\blue{1344 {cm}^{2} }$

$\therefore \: \sf{ Area \: of \: triangle }= \bf \green{1344 {cm}^{2} }$

.

Hope it helpful.⭐️

@xXCuteQueenXx

Answer 2

Step-by-step explanation:

$\star\sf\underline \purple{QuestioN}::-$

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is.

$\star\sf\underline\green{Given} ::-$

Sides

A = 56cm

B = 60

C = 62

$\star\tt\underline \orange{To \: find}::-$

Area of triangle.?

$\star\tt\underline \pink{Formula}::-$

$\tt {Side = \frac{a + b + c}{c} }$

$\star\tt\underline \red{AnsweR}::-$

Using Heron's formula

Area of the triangle

$\sqrt{s(s - a) \: (s - b)(s - c)} \\ s = \frac{56 + 60 + 52}{2} \\ = > \red{84}$

$\tt{Area \: of \: triangle = } \green{\sqrt{84(84 - 60) \: (84- 56)(84 - 52)} } \\ \longrightarrow \sqrt{1806336} \\ \longrightarrow \bf\blue{1344 {cm}^{2} }$

$\therefore \: \tt{ Area \: of \: triangle }= \bf \orange{1344 {cm}^{2} }$

.

Hope it helpful.☃️

@Somya2563