the sides of a triangle are 5cm, 6cm, and 7cm. find the area of triangle in approximately.
Answers
Answered by
14
This problem can be solved by Heron’s Formula,
A=√s(s−a)(s−b)(s−c)
where S (0.5*(a+b+c)) is one half of the perimeter of the triangle, sometimes called the semi-perimeter.
A is the area of the triangle
And a,b,c are the sides of the triangle
So if a=3 cm ,b=5 cm and c=6 cm
thus , Using Heron’s Formula we get the semi-perimeter as 7 cm
and the area as
A= sqrt(7*(7–3)(7–5)(7–6))
thus A= sqrt(7*4*2*1)=sqrt(56)=7.48 sq. cm.
thus the area of the triangle with side 3 cm,5 cm and 6 cm is 7.48 sq cm.
hope you get your answer mate
follow me and and mark me as brainlist.
A=√s(s−a)(s−b)(s−c)
where S (0.5*(a+b+c)) is one half of the perimeter of the triangle, sometimes called the semi-perimeter.
A is the area of the triangle
And a,b,c are the sides of the triangle
So if a=3 cm ,b=5 cm and c=6 cm
thus , Using Heron’s Formula we get the semi-perimeter as 7 cm
and the area as
A= sqrt(7*(7–3)(7–5)(7–6))
thus A= sqrt(7*4*2*1)=sqrt(56)=7.48 sq. cm.
thus the area of the triangle with side 3 cm,5 cm and 6 cm is 7.48 sq cm.
hope you get your answer mate
follow me and and mark me as brainlist.
Answered by
20
Hey mate,
As we know that,
this triangle is scalene triangle.
Solution : S = a+b×c/2
Here , 5+6+7/2
= 18/2
= 9 cm
Area of a triangle = √s(s-a)(s-b)(s-c)
= √9(9-5)(9-6)(9-7)
=. √9×4×3×2
=. √216
=. 14.69 square.cms
(approx).
Hope it helps you
Thank you
Plz mark it as brainliest answer
As we know that,
this triangle is scalene triangle.
Solution : S = a+b×c/2
Here , 5+6+7/2
= 18/2
= 9 cm
Area of a triangle = √s(s-a)(s-b)(s-c)
= √9(9-5)(9-6)(9-7)
=. √9×4×3×2
=. √216
=. 14.69 square.cms
(approx).
Hope it helps you
Thank you
Plz mark it as brainliest answer
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