The sides of a triangle are 7 / (2 cm), 11 / (4 cm) and 16/5 cm. Find its perimeter.
Answers
Answered by
2
Answer:
p of triangle = sum of all sides
p = 7 /2 + 11/4 + 16 / 5
p = 7 × 10/2×10 + 11 × 5 / 4 × 5 + 16 × 4 / 5 × 4
p = 70/20 + 55 / 20 + 64 /20
p = 189/ 20 cm
Answered by
2
Answer:
perimeter of atriangle=sum of all sides
therefore, (7/2+11/4+16/5)cm
taking L.C.M of 2 ,4,5
L.C.M of 2,4,5, is 20
(7/2×10/10+11/4×5/5+16/5×4/4)cm
(70/20+55/20+64/20)cm
189/20cm
Hence,perimeter of triangle is 189/20 cm
Similar questions