Math, asked by patilnanda87, 3 months ago


The sides of a triangle are 7cm, 24cm, 25cm. What is its area ?​

Answers

Answered by rishita5706
2

√s(s-a)(s-b)(s-c) s= perimeter/2.

√28(28-7)(28-24)(28-25). s= 56/2=28

√28*21*4*3

=84

hope it helps

Answered by krishnakrmandal75
2

Answer:

Perimeter of the triangle = (7+24+25)cm

=56cm

semi perimeter of the triangle =56/2 =28cm

Now,area of the triangle =

√S(s-a)( s-b)(s-c)

=√28(28-7)(28-24)(28-25)

= √28(21*4*3)

= √28*252

= √7056

= 84 cm square

therefore, area of the triangle is 84 cm square

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