The sides of a triangle are 7cm, 24cm, 25cm. What is its area ?
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√s(s-a)(s-b)(s-c) s= perimeter/2.
√28(28-7)(28-24)(28-25). s= 56/2=28
√28*21*4*3
=84
hope it helps
Answered by
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Answer:
Perimeter of the triangle = (7+24+25)cm
=56cm
semi perimeter of the triangle =56/2 =28cm
Now,area of the triangle =
√S(s-a)( s-b)(s-c)
=√28(28-7)(28-24)(28-25)
= √28(21*4*3)
= √28*252
= √7056
= 84 cm square
therefore, area of the triangle is 84 cm square
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