Math, asked by tusharverma5710, 11 months ago

the sides of a triangle are 7cm ,24cm,and 25cm its area is

Answers

Answered by DevbratDimri
5
S = a+b+c/2
= 7+24+25/2
= 56/2
= 28
By Herone's formula,
Area of triangle = √s (s-a) (s-b) (s-c)
=√28 (28-7) (28-24) (28-25)
=√28 (21) (4) (3)
= √7056
= 84 square cm
Answered by Arbaazamjad
1

2s=7cm+24cm+25cm

S=56/2=28cm

S-a(28-7)=21cm

S-b (28-24)=4cm

S-c (28-25)=3cm

:. Area of the triangle=s (s-a )(s-b)(s-c)

=28×21×4×3

=7×2×2×7×3×2×2×3

=(2×2)×(2×2)×(3×3)×(7×7)

=2×2×3×7

=84cm

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