Question

the sides of a triangle are 8 CM 11 cm and 13 cm what is its area?( solve it by the heron's formula)​

Answer 1

Step-by-step explanation:

a=13,b=11,c=8

s=a+b+c/2

13+11+8/2

=32/2

=16.

Area of triangle =

Answer 2

Given:

• The sides of the triangle are 8cm,11cm and 13cm.

Need to find:

• Area of the triangle

$\huge \underline{ \mathbb{SOLUTION:-}}$

a = 8cm

b = 11cm

c = 13cm

Perimeter of the ∆ = a+b+c

$\large \implies{8 + 11 + 13}$

$\large \implies{32cm}$

Semi-perimeter = a+b+c/2

$\large \implies{ \frac{32}{2} cm}$

$\large \implies{16cm}$

Area of ∆ $\small \implies{ \sqrt{s(s - a)(s - b)(s - c)}}$

$\small \implies{ \sqrt{16(16 - 8)(16 - 11)(16 - 13)}}$

$\small \implies{ \sqrt{16 \times 8 \times 5 \times 3}}$

$\small \implies{ \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 3}}$

$\small \implies{2 \times 2 \times 2 \sqrt{2 \times 5 \times 3}} \\ \small \implies{8 \sqrt{30}}$