Question

The sides of a triangle are 8cm,15cm,17cm. Find its area

Answer 1

Answer: 60cm²

Step-by-step explanation:

s=(8+15+17)/2=20.

area of triangle =square root of (s(s-8)(s-15)(s-17))

=square root of(20(20-8)(20-15)(20-17)

=square root of(20*12*5*3)

= square root of(4*5*4*3*5*3)

=4*5*3=60cm^2.

Answer 2

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: QuEsTiOn :- \: \star}}}}}$

The sides of a triangle are 8cm,15cm,17cm. Find its area .

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$\red{\bigstar}$ Area $\large\leadsto\boxed{\rm\purple{ {60cm}^{2}}}$

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

Sides of the triangle respectively :-

A 8cm

B = 15cm

C = 17cm

$\Large{\underline{\underline{\bf{Find:-}}}}$

Area = ?

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

Area of triangle

$\sf a = {60cm}^{2}$

As per the given :+

A = 8cm

B = 15cm

C = 17cm

$\sf \: s = \frac{a + b + c}{2}$

Now , substitute A , B and C values, we get

$\sf \: s = \frac{8 + 15 + 17}{2}$

$\sf \implies \: s = \frac{40}{2}$

$\sf \implies \: s = 20$

s - a = 20 - 8 = 12

s - b = 20 - 15 = 5

s - c = 20 - 17 = 3

Area of triangle

$\sf \: A = \sqrt{s(s - a)(s - b)(s - c)}$

$\implies \sf \: A = \sqrt{20 \times 12 \times 5 \times 3}$

$\implies \sf \: A = \sqrt{3600}$

$\implies \sf \: \: A= {60}^{2}$

$\sf \implies \: A = {60cm}^{2}$

$\mathfrak{\huge{\pink{\underline{\underline{Hence}}}}}$

Area of triangle

$\sf A = {60cm}^{2}$

$\boxed{\sf\blue{Area \: of \: triangle [A] = \dfrac{{60cm}^{2}}}}$