Question

The sides of a triangle are 8cm, 15cm, and 17cm respectively. At each of its vertices,circles of radius 3.5 cm are drawn. What is the area of the triangle excluding the portion covered by the sectors of the circles​

Answer 1

Answer:

Is it a qestion??if it is not pls don't send like this

Step-by-step explanation:

huh her huge fh tub bug 4th st it bjfsc night cuts njfd boys gud hute just turn vhfc

Answer 2

Step-by-step explanation:

The sides of a triangle are 8 cm, 15 cm and 17 cm.

As we know,

17 = 8 + 15

289 = 64 + 225

289 = 289

Now we can say triangle is right angled triangle

Area of right angled triangle = (1/2) × Base × height = (1/2) × 8 × 15 = 60 cm2

Area Covered in triangle by 3 circles = (θ₁ /360) πR² + (θ₂ /360) πR² + (θ₃ /360)πR² = [(θ₁ + θ₂ + θ₃)/360] × πR²

As we know,

θ₁ + θ₂ + θ₃ = 180°

Area Covered in triangle by 3 circles = [(θ₁ + θ₂ + θ₃)/360] × πR² = [180/360] × [22/7] × 3.5 × 3.5 = 19.25 cm2

Area of the triangle excluding the portion covered by the sectors of the circles = 60 - 19.25 = 40.75 cm2

Please mark me brainliest