The sides of a triangle are given by 3x²-y² ; 4x²-7xy+4y² and -3x² +7xy+8y². Find its perimeterhehelp
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6
Answer:
4x^2+11y^2
Step-by-step explanation:
perimeter of triangle ABC = AB + BC +AC
= 3x^2-y^2+4x^2-7xy+4y^2-3x^2+7xy+8y^2
= 4x^2+11y^2
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3
Answer:
answer
Step-by-step explanation:
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