The sides of a triangle are given by 3xsquare - y square;4x square - 7xy +4y square and -3x square +7xy+8y square. Find its perim6
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perimeter of triangle ABC = AB + BC +AC
= 3x^2-y^2+4x^2-7xy+4y^2-3x^2+7xy+8y^2
= 4x^2+11y^2
= 3x^2-y^2+4x^2-7xy+4y^2-3x^2+7xy+8y^2
= 4x^2+11y^2
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