Question

the sides of a triangle are given by x,2x+2 and 3x-2.If its perimeter is 30cm then find the smallest side of a triangle​

Answer 1

Answer:

Hii,

Brainliest plzz..

@Cutyjanu143

Answer 2

Given :–

• First side = x
• Second side = 2x + 2
• Third side = 3x – 2
• Perimeter of a triangle = 30cm.

To Find :–

• Smallest side of a triangle.

Solution :–

Let,

• The first side of a triangle be a.
• The second side of a triangle be b.
• The third side of a triangle be c.

First, we need to find the value of x.

We know that,

Perimeter of a triangle = 30cm.

↣ a + b + c = 30cm

Given,

• a = x
• b = 2x + 2
• c = 3x – 2

Now, put all the given values in the formula of perimeter of a triangle.

↣ x + (2x + 2) + (3x – 2) = 30cm

Now, open the brackets.

↣ x + 2x + 2 + 3x – 2 = 30

↣ x + 2x + 3x + 2 – 2 = 30

↣ 3x + 3x + 0 = 30

↣ 6x = 30

↣ x = $\dfrac{\cancel{30}}{\cancel{6}}$

↣ x = 5

Now, we have to find the values of all the sides.

Put the value of x in all the angles.

➲ a = x

↣ 5cm.

➲ b = 2x + 2

↣ 2(5) + 2

↣ 10 + 2

↣ 12cm.

➲ c = 3x – 2

↣ 3(5) – 2

↣ 15 – 2

↣ 13cm.

Hence,

The smallest side of a triangle is a (5cm).