the sides of a triangle are in the ratio 1/4:1/5:1/3 and it's perimeter is 141 CM. find the length of each side.
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Let the ratios be 1/3x, 1/4 x and 1/5x.
We know,
Perimeter of a triangle = a+b+c
=>141 = 1/3x+1/4x+1/5x
=> 141 = x/3 + x/4 + x/5
=> 141 = 20x+15x+12x/60 [taking the LCM of 3, 4 and 5 as 60]
=> 141 = 47x/60
=> 47x = 141*60
=> 47x = 8460
=> x = 8460/47
=> x = 180
Therefore, 1/3x = 1/3*180 = 60cm
1/4x = 1/4*180 = 45cm
1/5x = 1/5*180 = 36cm
We know,
Perimeter of a triangle = a+b+c
=>141 = 1/3x+1/4x+1/5x
=> 141 = x/3 + x/4 + x/5
=> 141 = 20x+15x+12x/60 [taking the LCM of 3, 4 and 5 as 60]
=> 141 = 47x/60
=> 47x = 141*60
=> 47x = 8460
=> x = 8460/47
=> x = 180
Therefore, 1/3x = 1/3*180 = 60cm
1/4x = 1/4*180 = 45cm
1/5x = 1/5*180 = 36cm
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