The sides of a triangle are in the ratio 15:14:13. Its perimeter is 168cm . Find out the area of the Triangle.
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Answer:
Step-by-step explanation:
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LET,THE SIDES OF A TRIANGLE BE
15x , 13x , 14x
HERE, a = 15x
b = 13x
c = 14x
SO,
THE PERIMETER OF A TRIANGLE(2S) = 168CM
a + b. + c = 168
⇒ 15x. + 13x. + 14x. = 168
⇒ 42x. = 168
⇒ x. = 4
∴ a. = 15x. = 15×4=60
b. = .13x = 13×4=52
c = 14x. = 14×4=56
SEMI PERIMETER. (S)
= 168/2=84cm.
∴ AREA = √s (s - a)(s - b)(s - c)
= √ 84(84 - 60)(84-52)(84-56)
= √ 84× 24 × 32 × 28
= √...(.approx )
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LET,THE SIDES OF A TRIANGLE BE
15x , 13x , 14x
HERE, a = 15x
b = 13x
c = 14x
SO,
THE PERIMETER OF A TRIANGLE(2S) = 168CM
a + b. + c = 168
⇒ 15x. + 13x. + 14x. = 168
⇒ 42x. = 168
⇒ x. = 4
∴ a. = 15x. = 15×4=60
b. = .13x = 13×4=52
c = 14x. = 14×4=56
SEMI PERIMETER. (S)
= 168/2=84cm.
∴ AREA = √s (s - a)(s - b)(s - c)
= √ 84(84 - 60)(84-52)(84-56)
= √ 84× 24 × 32 × 28
=1344
Hope it is helpful.