Question

The sides of a triangle are in the ratio 16:18:25 and its perimetre is 590 m find the smallest side of a triangle

Answer 1

hiii!!!

here's ur answer...

let the side of the triangle be 16x, 18x and 25x.

perimeter of the triangle = 590m

therefore 16x + 18x + 25x = 590m

==> 59x = 590m

==> x = 590/59

==> x = 10m

hence, sides of the triangle :-

16x = 16 × 10

= 160m

18x = 18 × 10

= 180m

25x = 25 × 10

= 250m

VERIFICATION :-

perimeter of the triangle = sum of all sides

= 160 + 180 + 250

= 590m

hence verified

the smallest side of the triangle is 160m.

hope this helps..!!

Answer 2

Heya.......!!!!

-- Given in the question :

=> ratio of sides of triangle = 16 : 18 : 25

=> Perimeter of triangle = 590 m

Let the sides be 16x , 18x , 25x
=> 16x + 18x + 25x = 590
=> 59x = 590
=> x = 10

Now ,, the sides of triangle are -

1.) 16x = 16 × 10 = 160 m
2.) 18x = 18 × 10 = 180 m
3.) 25x = 25 × 10 = 250 m

♦ Smallest side of triangle is = 160 m .

Hope It Helps You ^_^