Question

The sides of a triangle are in the ratio 2:3:4. the longest side is 20 cm more than the shortest side. calculate the length of all three sides.

Answer 1

Answer.

Let the sides of the triangle be AB, BC and AC

AB =2x

BC= 3x

AC =4x

AC = 20 + AB

=20 + 4x

AB^2+BC^2=AC^2

2x^2 + 3x^2 = (20+4x)^2

=20^2 +2×20×4x +4x^2 + 4x^2

Answer 2

Answer:

The length of all three sides of triangle is 20 cm , 30 cm , 40 cm

Step-by-step explanation:

Given as :

The ratio of three sides of triangle = 2 : 3 : 4

Let The sides be 2 x  , 3 x , 4 x

So, The longest side = 4 x

The shortest side = 2 x

And

The measure of longest side = 20 cm + The measure of shortest side

i.e 4 x = 20 cm + 2 x

Or, 4 x - 2 x = 20 cm

Or, 2 x = 20 cm

∴  x = $\dfrac{20}{2}$

i.e x = 10

So, The measure of shortest side = 2 x = 2 × 10 = 20 cm

The measure of middle side = 3 x = 3 × 10 = 30 cm

The measure of longest side = 4 x = 4 × 10 = 40 cm

Hence, The length of all three sides of triangle is 20 cm , 30 cm , 40 cm . Answer