Question

The sides of a triangle are in
the ratio 3:4:5. If it's primeter
is 36 cm, area of triangle is,

may I knw this question belongs to which class??and chapter??​

Answer 1

Answer:

let the side be x

3x+4x+5x= 36=12x=36x=36/12= 3

3 us the value of x then 3×3=9 like this all

Answer 2

Answer:

54√3 cm^2

Step-by-step explanation:

Let the sides of the triangle be x

and, perimeter of the triangle = 36cm

so, 3x+4x+5x = 36 cm

12x =36

x = 36/12

x= 3

1st side= 3*3 = 9

2nd side = 3*4 = 12

3rd side = 3*5 =15

By heron's formula

s= a+b+c/2. ( a=9, b=12, c=15)

s= 9+12+15/2

s= 36/2

s= 18

Area of the triangle = √s(s - a)(s - b)(s - c)

= √18(18-9)(18-12)(18-15)

= √18(9)(6)(3)

= √(2*3*3*3*3*3*3*2*3). (we will take the common ones outside the bracket)

= 2*3*3*3*√3

= 54√3 cm^2

May be this question belongs to (NCERT) class 9th and 12th chapter ( Heron's Formula).

Please say thanks to me mark as the brainliest.