Math, asked by dhruvkapoor, 1 year ago

the sides of a triangle are in the ratio 3:4:5 . if perimeter of triangle is 144m find the area of triangle

Answers

Answered by examguru1
1

let the sides of triangle be 3x,4xand 5x respectively.

perimeter of triangle= sum of its sides

144=3x+4x+5x

144=12x

x=12.

therefore sides of triangle are 3x= 36cm

4x=48cm

And 5x= 60cm.

area of triangle by heron's formula

s= 36+48+60/2=72

area is

√s(s-36)(s-48)(s-60)

√72(72-36)(72-48)72-60)

area becomes

864cm^2

Answered by MISSTHUNDER
15

ⓢⓞⓛⓤⓣⓘⓞⓝ ⤵️

ratio of the sides =3:4:5

perimeter of the triangle=144m

we know that perimeter of a triangle=a+b+c(here a,b and c are the sides )

here first side =3x

second side =4x

and third side =5x

according to the question,

3x+4x+5x=144

or,12x=144

or,x=144/12(dividing both sides by 12)

or,x=12

length of first side=12×3=36m

length of second side =12×4=48m

length of the third side =12×5=60m

✯Triangle✯

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted \triangle ABC. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane.

Area: ½ × base × height

Perimeter: sum of side lengths of the triangle

Number of vertices: 3

Number of edges: 3

Internal angle: 60° (for equilateral)

Sum of interior angles: 180°

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