Math, asked by Umkenandkishor8257, 1 year ago

the sides of a triangle are in the ratio 3:5:7 and its perimeter is 300m. find its area

Answers

Answered by Akv2
396
Let coefficient of ratios be X.
then,
3x+5x+7x=300
15x=300
X=20

Sides of triangle are :-
60 m + 100 m + 140 m

By Heron's formula,
We have,
s =  \frac{a + b + c}{2}  \\ s =  \frac{300}{2}  \\ s = 150 \\ area =  \sqrt{s(s - a)(s - b)(s - c)}  \\  =  \sqrt{150(150 - 60)(150 -100)(150 - 140)}  \\  =  \sqrt{150 \times 90 \times 50 \times 10} \\  =   \sqrt{15 \times 9 \times 5 \times 10000}  \\   = \sqrt{75 \times  {3}^{2}  \times  {10}^{4} }  \\  =  \sqrt{75}  \times 3 \times  {10}^{2}  \\  =  \sqrt{75}  \times 300 \\  =  \sqrt{25 \times 3}  \times 300 \\  =  \sqrt{ {5}^{2}  \times 3} \times 300 \\  = 1500 \times  \sqrt{3}  \\  = 1500 \sqrt{3}  {m}^{2}
Answered by shaidhrees
66

Let coefficient of ratios be X.

then,

3x+5x+7x=300

15x=300

X=20

Sides of triangle are :-

60 m + 100 m + 140 m

By Heron's formula,

We have,

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