the sides of a triangle are in the ratio 5:12:13 and its perimeter is 150cm. find the area of triangle
Answers
Answered by
62
let the sides of the triangle be 5x,12x,13x.
a/q 5x+12x+13x=150
=> 30x=150
=>x=5
therefore, sides are 25cm,60cm,65cm.
now,
area of triangle = 1/2 x b x h
= 1/2 x 25 x 60 = 750 sq.cm
hope this will help.
a/q 5x+12x+13x=150
=> 30x=150
=>x=5
therefore, sides are 25cm,60cm,65cm.
now,
area of triangle = 1/2 x b x h
= 1/2 x 25 x 60 = 750 sq.cm
hope this will help.
Answered by
14
let the sides be--5x,12x,13x...
Perimeter of triangle=150cm
so, 5x+12x+13x=150
30x=150
x=5
so,....sides will be
5x= 5×5=25cm
12x= 12×5=60cm
13x= 13×5=65cm
Area of triangle =
S=a+b+c/2
![s = \sqrt{s(s - a)(s - b)(s - c} s = \sqrt{s(s - a)(s - b)(s - c}](https://tex.z-dn.net/?f=s+%3D++%5Csqrt%7Bs%28s+-+a%29%28s+-+b%29%28s+-+c%7D+)
S=25+60-65/2
=150/2
=75
![s = \sqrt{75(75 - 25)(75 - 60)(75 - 65)} s = \sqrt{75(75 - 25)(75 - 60)(75 - 65)}](https://tex.z-dn.net/?f=s+%3D++%5Csqrt%7B75%2875+-+25%29%2875+-+60%29%2875+-+65%29%7D+)
![s = \sqrt{75(50)(15)(5)} s = \sqrt{75(50)(15)(5)}](https://tex.z-dn.net/?f=s+%3D++%5Csqrt%7B75%2850%29%2815%29%285%29%7D+)
![s = \sqrt{75 \times 15 \times 5 \times 50 } s = \sqrt{75 \times 15 \times 5 \times 50 }](https://tex.z-dn.net/?f=s+%3D++%5Csqrt%7B75+%5Ctimes+15+%5Ctimes+5+%5Ctimes+50+%7D+)
![s = \sqrt{?} 281250 s = \sqrt{?} 281250](https://tex.z-dn.net/?f=s+%3D+++%5Csqrt%7B%3F%7D+281250)
![s = 530.33 s = 530.33](https://tex.z-dn.net/?f=s+%3D+530.33)
..
hope its help uhhh
Perimeter of triangle=150cm
so, 5x+12x+13x=150
30x=150
x=5
so,....sides will be
5x= 5×5=25cm
12x= 12×5=60cm
13x= 13×5=65cm
Area of triangle =
S=a+b+c/2
S=25+60-65/2
=150/2
=75
..
hope its help uhhh
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