the sides of a triangle are in the ratio 5:12:13 and its perimeter is 150 m. find the ar. of triangle
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Answered by
3
Let the sides of triangle be 5x,12x&13x
It is clear that
(13x)^2 =(5x)^2 +(12x)^2
So triangle is a right angle triangle
Perimeter =150
5x+12x+13x=150
30x=150
x=5m
So sides are 25,60,65
In this triangle 65 is hypotenuse and others are perpendicular and base
So area of triangle =1/2)xbasexheight
=1/2x25x60
=30x25
=750msquare
It is clear that
(13x)^2 =(5x)^2 +(12x)^2
So triangle is a right angle triangle
Perimeter =150
5x+12x+13x=150
30x=150
x=5m
So sides are 25,60,65
In this triangle 65 is hypotenuse and others are perpendicular and base
So area of triangle =1/2)xbasexheight
=1/2x25x60
=30x25
=750msquare
Answered by
0
let the ratio constant be x.
So sides of triangle are 5x,12x,13x
perimeter of triangle=150
now,
Perimeter of triangle=sum of all sides
150=5x+12x+13x
150=30x
150/30=x
5=x
now,
putting value of x in
5x=5*5
=25
12x=12*5
=60
13x=13*5
= 65
So sides of triangle are 5x,12x,13x
perimeter of triangle=150
now,
Perimeter of triangle=sum of all sides
150=5x+12x+13x
150=30x
150/30=x
5=x
now,
putting value of x in
5x=5*5
=25
12x=12*5
=60
13x=13*5
= 65
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