the sides of a triangle are in the ratio 7:5:8. if its permeter is 440cm , find the sides of the triangle
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5
let the ratios be 7x + 5x + 8x
sum= 20x
therefore:
20x= 440
x= 440/20
= 22.
Therefore he sides are : 7*22 ,5*22,8*22=≥ 154 ,120 ,176 are the sides.
sum= 20x
therefore:
20x= 440
x= 440/20
= 22.
Therefore he sides are : 7*22 ,5*22,8*22=≥ 154 ,120 ,176 are the sides.
Pranavbhat16:
ia that the correct ans??
Answered by
1
Answer:
Perimeter of triangle=440
Let the side of triangle be x
Measures of the side of triangle in ratio=7:5:8
=7x:5x:8x
Perimeter of triangle=7x +5x+8x
440= 20x
20/440=x
22=x
∆ 7x=7*22
= 154
∆ 5x= 5*22
= 110
∆ 8x=8*22
= 176
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