the sides of a triangle are in the ratio of 3:4:5 if it's perimeter is 36 then find its area
Answers
Step-by-step explanation:
The area of triangle is 54 cm².
Step-by-step explanation:
It is given that the sides of a triangle are in the ratio 3 : 4 : 5.
Let the length of sides are 3x, 4x and 5x.
It's perimeter is 36 cm.
3x+4x+5x=363x+4x+5x=36
12x=3612x=36
x=3x=3
The value of x is 3. The length of sides are 9, 12, 15.
It is an right angled triangle because the sum of squares of two smaller sides is equal to the square of larger sides.
9^2+12^2=15^2=225
+12
=15
=225
Here, the length of hypotenuse is 15 cm.
The area of triangle is
A=\frac{1}{2}\times base \times heigthA=
2
1
×base×heigth
A=\frac{1}{2}\times 9 \times 12A=
2
1
×9×12
A=54A=54
Therefore the area of triangle is 54 cm².
Answer:
since the sides r in the ratio 3:4:5
so, it's a right angled ∆
now, 3x +4x +5x=36
x=3
now area of ∆=1/2(base × height)
= 1/2(9×12)
=54..