The sides of a triangle are in the ratio of 6 : 18 : 25 and its perimeter is 590 meters. find the smallest side of the triangle.
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Answered by
1
Let the sides be 6x, 18x, 25x
perimeter of triangle = 590m
sum of all sides = 590
6x + 18x + 25x = 590
49x = 590
x = 590/49 = 12.04m
the sides are :-
1) 6x = 6 × 12.04 = 72.24m
2) 18x = 18 × 12.04 = 216.72m
3) 25x = 25 × 12.04 = 301m
1st side is the smallest side
perimeter of triangle = 590m
sum of all sides = 590
6x + 18x + 25x = 590
49x = 590
x = 590/49 = 12.04m
the sides are :-
1) 6x = 6 × 12.04 = 72.24m
2) 18x = 18 × 12.04 = 216.72m
3) 25x = 25 × 12.04 = 301m
1st side is the smallest side
Answered by
0
side of triangle is 6x,18x&25x
the perimeter of the triangle is 590m
6x+18x+25x=590
49x=590
x=590/49
x=12.04
So, the first side is 12.04*6=72.24
second side is 12.04*18=216.72
third side is 25*12.04=301
So, the first side is the smallest side of the triangle
the perimeter of the triangle is 590m
6x+18x+25x=590
49x=590
x=590/49
x=12.04
So, the first side is 12.04*6=72.24
second side is 12.04*18=216.72
third side is 25*12.04=301
So, the first side is the smallest side of the triangle
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