The sides of a triangle are (m+3n) cm,(3m+2n-2) cm and (4m+n/2+1) cm. If the triangle is equilateral triangle, find its perimeter
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D
21 cm
Sides of equilateral Δ are (2a−b) cm, (a+3b) cm & (2a−2b+1) cm
As all the sides are equal.
∴2a−b=a+3b
a=4b
a+3b=2a−2b+1
a=5b−1
4b=5b−1
b=1 cm
∴a=4 cm
∴ Perimeter of equilateral Δ=2a−b+a+3b+2a−2b+1
=5a+1
=21 cm
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