Math, asked by srgmath6206, 1 year ago

The sides of a triangle are of lengths 8cm, 15cm and 17cm. find area and the length of the altitude drawn on the side with length 17cm.


yashvigupta345: Is this question from the chapter Heron's Formula??

Answers

Answered by yashvigupta345
4

Area of triangle=√s(s-a)(s-b)(s-c)

=√40(40-15)(40-17)(40-8)

=√40×25×23×32

=√(2×2)×2×5 × (5×5) × 23 × (2×2)×(2×2)×2

=2×2×2×5√5×(2×2)×23

=2×2×2×2×5√5×23

=80√115 cm²


Base=17 cm

Area of triangle= base×height

80√115=17×h

h=80√115/17

h=50.46 cm


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