Question

The sides of a triangle are :$18cm^{2} ,24cm^{2} and 30cm^{2}$
Area of triangle=--------cm sq.
The altitude of the smallest side_____

Answer 1

▪︎According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is

$a = \sqrt{s(s - a)(s - b)(s - c)}$

wheres = a+b+c/2

For the given triangle,a=18 cm b=24 cm c=30 cm

♡. s = 18+24+30/2

=36

A = √ 36(36−18)(36−24)(36−30)

A = √ 36×18×12×6

6×18×12×6A = √ 216×216

{ A = 216 cm² }

Smallest side =18 cm

☆. Area of the triangle = 1/2 ×base×altitude = 216×1/2×18× altitude = 216

Altitude = 216/9

. =24 cm

♥️. HOPE THIS WILL HELP YOU BUDDY.....