The sides of a triangle are x, 2x+1, x+2 for some positive rational number x. if one angle of the triangle is 60°, what is the perimeter of the triangle? PLZ tell
ANSWER WITH EXPLANATION PLEASE.
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Answer:
since 60 degree will be second highest angle
therefore Cos 60 =[ x^2 +(2x + 1)^2 - (x+2)^2]÷[2 x (2x+ 1)]
since cos A = (b^2+ c^2- a^2)/2bc
where a is side opp to angle A
therefore x= 3/2
and the pereter is equal to 4x +3
which is equal to 9 units
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