Question

The sides of a triangle are, x,x+1, 2x-1 and area is x square root10. Find the value of x​

Answer 1

Hey mate!!

Sides of a triangle are

a = x,

b = x+1,

c = 2x-1

 

area = x√10

Area = √(s(s-a)(s-b)(s-c))

 

s = (a+b+c)/2

s = (x+(x+1)+(2x-1))/2

s = 2x

x√10 = √(2x(2x-x)(2x-(x+1)(2x-(2x-1))

x = 6

Hope helps!!