Math, asked by ishthefish2006, 6 months ago

The sides of a triangle are x, x + 1, 2x -1 and its area is x√10. What is the value of x?

Answers

Answered by hanshu1234
2

Step-by-step explanation:

Let the width of the given rectangle = x M, then

The length of the given rectangle = x M

We know, area of the rectangle = width X length

=> Area of the rectangle = x X 2x

=> Area of the rectangle = 2 x^2

Area of the given rectangle = 14450 M^2

=> 2 x^2 = 14450

=> (2 x^ 2 ) / 2 = 14450 / 2

=> x^2 = 7225 = (85)^2

Taking square root of both sides, we get

=> x = +-(85)

Length always be positive, therefore

=> x = 85

We know, perimeter of the rectangle = 2 ( width + length )

=> Perimeter of the rectangle = 2(x + 2x ) = 2 ( 3x) = 6x

Put x = 85 , we have

=> Perimeter of the rectangle = 6(85)

=> Perimeter of the rectangle = 510 M Answer

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