Question

The sides of a triangle are x°-3xy+8,
4x°+ 5xy-3 and 6-3x² + 4xy
find its perimeter.​

Answer 1

Step-by-step explanation:

hey mate here is your answer:

given,

sides of triangle:

1) x-3xy+8

2)4x+5xy-3

3)6-3x+4xy

to find,

perimeter of triangle.

required formula:

$perimeter \: of \: triangle = sum \: of \: the \: sides \: of \: a \: triangle$

solution,

perimeter of triangle=

=x-3xy+8+4x+5xy-3+6-3x+4xy

=x+4x-3x+3xy+5xy+4xy+8-3+6

=2x+12xy+11

.: perimeter of triangle= 2x+12xy+11