Question

The sides of a triangle are x2+5x−2, 5x2+9x+5, 2x2+5.Then the perimeter is…

Answer 1

Given :-

★ $\sf{Sides \:of\: triangle }$

1. $\sf{\ x^{2}+5x-2}$
2. $\sf{5\ x^{2}+9x+5}$
3. $\sf{2\ x^{2}+5}$

To Find :-

★ Perimeter of Triangle

Answer :-

★ $\sf{8\ x^{2}+14x+8}$

Formula :-

★$\sf{Perimeter\:of\: Triangle\:=\:Sum\:of\:all\: sides}$

Solution :-

$\bf{Perimeter\:=\:Sum \:of\:all\:sides}$

$\mapsto\sf{\ x^{2}+5x-2+5\ x^{2}+9x+5+2\ x^{2}+5}$

$\mapsto\sf{8\ x^{2}+14x+8}$

$\sf{ }$

$\sf{ \underline{ \underline{So,\: Perimeter\:is\:8\ x^{2}+14x+8}}}$

Answer 2

Answer:

Perimeteris8 x2+14x+8