Question

the sides of a triangle are56cm60cmand52cm long then the area of the triangle​

Answer 1

Answer:

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is

(a) 1322 cm2

(b) 1311 cm2

(c) 1344 cm2

(d) 1392 cm2

Thinking Process

(i) First, determine the semi-perimeter of a triangle by using the formula, s = (a + b + c)/2

(ii) Further, determine the area of triangle by using the formula, area of triangle (Fieron’s formula) =

Answer 2

Answer:

✮Formula used:

$Area= \sqrt{s(s - a)(s - b)(s - c}$

✮Solution:

Perimeter of the rectangle= a+b+c

⇒Semi-perimeter of the rectangle= (a+b+c)/2

$⇒ \frac{56 + 60 + 52}{2} \\ \\ ⇒ \frac{168}{2} \\ \\ ⇒84cm$

$⇒Area= \sqrt{84( 84- 56)(84- 60)(84 - 52)}$

$Area = \sqrt{84 \times 28 \times 24 \times 32}$

$⇒Area = \sqrt{1806336}$

$⇒Area =1344 {cm}^{2}$

Therefore, The area of the triangle is 1344cm².