Question

The sides of a triangle are6.5cm,7cm,7.5cm. A parallelogram stands on side of length 7cm and has the same area as the of the triangle . Find the height of the parallelogram

Answer 1

let a triangle Sides are AB=6.5cm
BC=7cm and AC=7.5cm
S=6.5+7+7.5/2=21/2=10.5
Area of ΔABC=sqrt S(S-AB) (S-BC) (S-AC)
=sqrt10.5(10.5-6.5)(10.5-7)(10.5-7.5)
=sqrt10.5(4)(2.5)(3)
sqrt10.5×12×2.5=√315=17.75
:. Area of ΔABC=17.78cm²
A/Q
Area of ΔABC= Area of Parallegram
=)17.5cm²=base×hight
:.hight=17.5/7(therefore length is given)
=)hight=2.5cm
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