Question

the sides of a triangle area 25 cm , 39 cm, and 56 cm . find the altitude a​

Answer 1

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Let a=25 m, b=39 m, c=56 m

semi-perimeter, s= a+b+c/2

s= 25+39+56/2

s= 120/2

=60 m

Area of triangle= √s(s−a)(s−b)(s−c)

= √60(60−25)(60−39)(60−56)

= √60(35)(21)(4)

= √176400

=420 m

Area of triangle= 1/2 × base × height

base=greatestside=56 m

420= 1/2(56) h

h = 840/56

h=15 m

Hence, the altitude or Height is 15