The sides of a triangle be three consecutive natural number such that its largest angle is twice the smallest. Then the value of the least side is
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Answer:
5
Step-by-step explanation:
Using sine law,
n−1sinα=n+1sin2α
⇒2cosα=(n−1)n+1
⇒cosα=2(n−1)n+1
∴2n(n+1)n2+(n+1)2−(n−1)2=2(n−1)(n+1) (using cosine law)
⇒2n+(n+1)n2+4n=2(n−1)(n+1)
⇒2(n+1)n+4=2(n−1)n+1
(n+1)⇒2(n+1)n+4=2(n−1)n+1⇒(n+1)2=(n+1⇒2n+(n+1)n2+4n=2(n−1)(n+1)
⇒2(n+1)n+4=2(n−1)n+1
∴n=5
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