the sides of A triangle can be 6cm, 7c, and 20cm (T/F)
PLEASE explain properly / give step by step answer
Answers
Question:
- the sides of A triangle can be 6cm, 7c, and 20cm (T/F)
property Used :
- The sum of 2 sides of triangle are always greater than the third side
- The difference of the 2 sides are always less than the third side
Checking:
The sum of 2 sides of triangle are always greater than the third side = According to this
- 7 + 4 = 13
✓ Here it's correct let's see the next one
The difference of the 2 sides are always less than the third side = According to this
- 7 - 4 = 3
✓ Here too it's correct
- so 7 , 4 , 20 is the sides of the triangle
Hence the statement is true
Answer:
Average speed=total distance/total time
d=distance travelled at 30m/s and distance travelled at 40m/s … same distance
time=distance/speed
time at 30m/s =d/30
time at 40 m/s=d/40
total time=d/30 + d/40= 7d/120
average speed= (d+d)/(7d/120)= 240/7=34.2857 m/s
It is not the average of the speeds because he spends more time at 30 m/s then at 40 m/sAverage speed=total distance/total time
d=distance travelled at 30m/s and distance travelled at 40m/s … same distance
time=distance/speed
time at 30m/s =d/30
time at 40 m/s=d/40
total time=d/30 + d/40= 7d/120
average speed= (d+d)/(7d/120)= 240/7=34.2857 m/s
It is not the average of the speeds because he spends more time at 30 m/s then at 40 m/sAverage speed=total distance/total time
d=distance travelled at 30m/s and distance travelled at 40m/s … same distance
time=distance/speed
time at 30m/s =d/30
time at 40 m/s=d/40
total time=d/30 + d/40= 7d/120
average speed= (d+d)/(7d/120)= 240/7=34.2857 m/s
It is not the average of the speeds because he spends more time at 30 m/s then at 40 m/sAverage speed=total distance/total time
d=distance travelled at 30m/s and distance travelled at 40m/s … same distance
time=distance/speed
time at 30m/s =d/30
time at 40 m/s=d/40
total time=d/30 + d/40= 7d/120
average speed= (d+d)/(7d/120)= 240/7=34.2857 m/s
It is not the average of the speeds because he spends more time at 30 m/s then at 40 m/sAverage speed=total distance/total time
d=distance travelled at 30m/s and distance travelled at 40m/s … same distance
time=distance/speed
time at 30m/s =d/30
time at 40 m/s=d/40
total time=d/30 + d/40= 7d/120
average speed= (d+d)/(7d/120)= 240/7=34.2857 m/s
It is not the average of the speeds because he spends more time at 30 m/s then at 40 m/sAverage speed=total distance/total time
d=distance travelled at 30m/s and distance travelled at 40m/s … same distance
time=distance/speed
time at 30m/s =d/30
time at 40 m/s=d/40
total time=d/30 + d/40= 7d/120
average speed= (d+d)/(7d/120)= 240/7=34.2857 m/s
It is not the average of the speeds because he spends more time at 30 m/s then at 40 m/s