Question

the sides of a triangle ground are 5m7m and 8 m respectively .find the cost of leveling the ground at the rate if rupees 10 per m ²

Answer 1

$<b >Hey here is your answer$

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Sides of the triangular ground :-

=> 5m
=> 7m and
=> 8m

semi - perimeter of the triangular ground :-

s = $\bf \frac{(a + b + c)}{2}$

( here a , b and c are sides of the triangle )

s = $\bf \frac{(5m + 7m + 8m)}{2}$
s = $\bf \frac{20m}{2}$
s = 10m

Area of triangle by Heron's formula :-

$\bf = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \bf \sqrt{10(10 - 5)(10 - 7)(10 - 8)} \\ \\ \bf = \sqrt{10 \times 5 \times 3 \times 2} \\ \\ \bf = \sqrt{2 \times 5 \times 5 \times 3 \times 2} \\ \\ = \bf \sqrt{2 \times 2 \times 5 \times 5 \times 3} \\ \\ \bf = 2 \times 5 \sqrt{3} \\ \\ \bf = 10 \sqrt{3} \: \: {m}^{2}$

Now ,

cost of leveling the ground at per m^2 => rs 10

Now , cost of leveling the ground at 10√3 m^2 = 10√3 × 10 rs

= 100√3 rs

or,

100 × 1.732 rs
= 173.2 rs

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Hope this helps you

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