The sides of
a triangle
in the ratio 2: 3:4 if the
Perimeter is 108m, find the area of the
triangle
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1
Answer:
hope it will help you.....
Step-by-step explanation:
let side be 2x, 3x, 4x
perimeter of triangle= 108m
=> a+b+c= 108
2x+3x+4x=108
9x=108
x=108/9
x=12
side of triangle are =
a= 2x= 2×12 = 24m
b= 3x= 3×12 = 36m
c= 4x= 4×12 = 48m
by heron's formula,
s = (a+b+c)/2
= (24+36+48)/2
= 108/2
= 54
area = √s(s-a)(s-b)(s-c)
= √54(54-24)(54-36)(54-48)
= √54×30×18×6
= 418.2m^2
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