Question

The sides of a triangle is 56 cm 60 cm and 52 cmThe area is

Answer 1

$let \: a = 56cm \\ b = 60cm \\ c = 52cm \\ s = \frac{(56 + 60 + 52)}{2} \\ s = \frac{168}{2} \\ s = 84 \\ area = \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{84 \times 28 \times24 \times 32 } \\ = \sqrt{1806336} \\ = 1344 {cm}^{2}$