Question

The sides of a triangle, taken in order are each 3 cm longer than the preceeding side. If the
perimeter of the triangle is 81 cm. Find the sides of triangle.​

Answer 1

According to the question:
AB=x cm
BC=x+3 cm
CA=x+6

Perimeter=AB +BC+CA
x+x+6+x+3=81
3x+9=81
3x= 81-9
3x=72
x=72/3
x=24

Therefore;
AB=24 cm
BC=27 cm
CA= 30 cm

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Answer 2

Question :-

The sides of a triangle, taken in order are each 3 cm longer than the preceeding side. If theperimeter of the triangle is 81 cm. Find the sides of triangle.

Given :-

★ The sides of a triangle, taken in order are each 3 cm longer than the preceeding side.

★ Perimeter of triangle = 81 cm.

Solution :-

Let the sides of triangle are 'x', 'x+3' and 'x+3+3 = x+6'

Perimeter is 81 cm. ----------------( Given )

So,

We know that , perimeter = sum of all sides

Therefore, 81 = x + x + 3+ x + 6

⟶ x + x + x + 3 + 6 = 81

⟶ 3x + 9 = 81

⟶ 3x = 81 - 9

⟶ 3x = 72

⟶ x = 72 / 3

⟶ x = 24

Now, put the value of x in their sides ,

therefore,

⟹ x = first side = 24cm

⟹ x + 3 = second side = 24 + 3 = 27 cm

⟹ x + 6 = third side = 24 + 6 = 30 cm

So, The sides of triangle are 24cm,27cm and 30 cm.