Question

the sides of a triangles are l,(l+1),and 13 cm If it's perimeter is 56cm ,then find the value of l​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:l=21\:cm}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Sides \: of \: triangle = (l),(l + 1) \: and \: 13 \\ \\ \tt: \implies Perimeter \: of \: triangle = 56 \: cm \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Value \: of \: l = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Perimeter \: of \: triangle = 56 \: cm \\ \\ \tt: \implies l + l + 1 + 13 = 56 \\ \\ \tt: \implies 2l + 13 = 56 \\ \\ \tt: \implies 2l = 56 - 14 \\ \\ \tt: \implies 2l = 42 \\ \\ \tt: \implies l = \frac{42}{2} \\ \\ \green{\tt: \implies l = 21\: cm} \\ \\ \green{\tt \therefore Value \: of \: l \: is \: 21 \: cm} \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \orange{\tt \circ \: Area \: of \: triangle = \frac{1}{2} \times b \times h} \\ \\ \orange{\tt \circ \: Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} }$

Answer 2

$\tt{\orange {\huge{Hello!!! }}} B.Q$

QUESTION :

The sides of a triangles are l,(l+1),and 13 cm If it's perimeter is 56cm ,then find the value of l

SOLUTION :

We know that the Perimeter of a triangle is equal to the sum of the lengths of it's sides.

Hence :

=> L + L + 1 + 13 .

=> 2 L + 14 = 56

=> 2 L = 42

=> L = 21

Answer : L = 21 cm.