Question

The sides of a triangular field are 15 1/3 m, 12 1/4 m and 9 1/6
m. Find the perimeter .


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Answer 1

Step-by-step explanation:

perimeter of triangle = sum of all sides

= 15 1/3 + 12 1/4 + 9 1/6

= 46/3 + 49/4 + 55/6

= ((46×4)+(49×3)+(55×2))/12

= (184+147+110)/12

=441/12

=36.75m

(15 1/3 is a mixed fraction

15 1/3 = ((15×3)+1)/3

= (45+1)/3

= 46/3 )

Answer 2

Answer:

change mixed fraction into improper fraction

15 1/3 m=46/3m

12 1/4 m=49/4m

9 1/6 m=55/6

perimeter = sum of sides

46/3 + 49/4 + 55/6

LCM of 3 , 4 and 6 is 12

= [(4×46)+(3×49)+(2×55)] /12

= [ 184+147+110 ] /12

= 441/12

= 441 ÷3 / 12÷3 (3 as HCF)

= 147/4

= 36 3/4 m or 36.75 m

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