Question

The sides of a triangular field are 41 m,40 m and 9 m.Find the number of rose beds that can be prepared in the field,If each rose bed on an average needs 900 cm square space?

Answer 1

area of triangle : a = 41 m ; b = 40 m c = 9 m

a+b+c/2

41+40+9/2

90/2

45

√s(s-a)(s-b)(s-c)

√45(45-41)(45-40)(45-9)

√45×4×5×36

√32400

180 m²

= 1800000 cm²

1 rose bed = 900 cm²

no of rose beds = 1800000/900

2000 rose beds  can be prepared in the field.

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