Question

The sides of a triangular field are 41m , 40m, 9m. find its area

Answer 1

Semi perimeter = 90/2 = 45

Now,

HERON'S FORMULA :-
$\sqrt{s(s - a)(s - b)(s - c)}$


$= > \: \sqrt{45(45 - 41)(45 - 40)(45 - 9)}$

$= > \: \sqrt{45 \times 4 \times 5 \times 36}$

$= > \: \sqrt{32400}$

$= > \: 180 {m}^{2}$

$.......... \: ANS$

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Answer 2

s=a+b+c/2
s=41+40+9/2=45m.
area=/s(s-a)(s-b)(s-c)
area=/45(45-41)(45-40)(45-9)
area=/45*4*5*36
area=/3*3*5*2*2*5*2*2*3*3
area=3*5*2*2*3
area=180m2.
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