the sides of a triangular field are 41m,40m,9m.find the numbers rose bed's that can be prepared in the filed, if each rose bed on an average needs 900msqure space
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By Heron's formula.
Area of a triangular= √s×(s-a)(s-b)(s-c) ,where a,b,c are sides of the triangle and s is the semi perimeter.
so, area of the field=√[45×(45-41)(45-40)(45-9)] = √(45 × 4 × 5 × 36) = √32400 = 180m^2 =1800000cm^2.
now, space needed for a flower bed = 900cm^2.
so, number of flower beds = 1800000/900 = 2000.
Area of a triangular= √s×(s-a)(s-b)(s-c) ,where a,b,c are sides of the triangle and s is the semi perimeter.
so, area of the field=√[45×(45-41)(45-40)(45-9)] = √(45 × 4 × 5 × 36) = √32400 = 180m^2 =1800000cm^2.
now, space needed for a flower bed = 900cm^2.
so, number of flower beds = 1800000/900 = 2000.
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