Question

The sides of a triangular field are 50m, 45m,and 35m.Find the number of flower beds that can be prepared if each bed measures 5m^2

Answer 1

HEY  THERE!!!

Question:-

The sides of a triangular field are 50m, 45m,and 35m.Find the number of flower beds that can be prepared if each bed measures 5m^2.

Method of Solution;-

Given:-

Sides Of a Triangular Field are 50 , 45, 35, metre.

Now, Using Formula of Semi - Perimeter!!

Let to be First Side = a

'' '' ''. Second Side = b

"""""""""" Third Side = c

Now, Semiperimeter = a+b+c/2

=> 50+45+35/2

=> 50+80/2

=> 130/2

=> 65

Now, Using Heron's Formula!!

Area = √s(s-a)(s-b)(s-c)

=> √65(65-50)(65-45)(65-35)

=> √65(15)(20)(30)

=> √ 585000

=> 764.85 metre

Now, According to the Question!!

Required number of flower beds that can be prepared if each bed measures 5m²

•°• => 764.85 ÷ 5

=> 152.97

Here, Approximately = 153

Hence, Required Number of flower beds = 153

Answer 2

Here is your solution

Given:-

Sides Of a Triangular Field are 50 , 45, 35, metre.

Let,

First Side = a

Second Side = b

Third Side = c

We know that

Semiperimeter = a+b+c/2

=> 50+45+35/2

=> 50+80/2

=> 130/2

=> 65

Hence semiperimeter is 65m

Using Heron's Formula

Area = √s(s-a)(s-b)(s-c)

=> √65(65-50)(65-45)(65-35)

=> √65(15)(20)(30)

=> √ 585000

=> 764.85 m²

Now, we have to find

Required number of flower beds that can be prepared if each bed measures 5m²

=> 764.85m² /5m²

=> 152.97

153(approx)

Hence,

Required Number of flower beds = 153

Hope it helps you